SOLUTION: find a value of k so that X+1 is a factor of P(x)=x^3+kx^2+x+6

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Question 1144607: find a value of k so that X+1 is a factor of P(x)=x^3+kx^2+x+6
Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
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x+1 is the factor of the polynomial  P(x) = x^3 + kx^2 + x + 6  if and only if the number -1 is the root of the polynomial


    P(-1) = 0,


according to the Remainder theorem.


    P(-1) = (-1)^3 + k*(-1)^2 + (-1) + 6 = 0


            -1     + k        - 1    + 6 = 0

                     k               + 4 = 0.

                     k                   = -4.    ANSWER

Solved.

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   Theorem   (the remainder theorem)
   1. The remainder of division the polynomial  f%28x%29  by the binomial  x-a  is equal to the value  f%28a%29  of the polynomial.
   2. The binomial  x-a  divides the polynomial  f%28x%29  if and only if the value of  a  is the root of the polynomial  f%28x%29,  i.e.  f%28a%29+=+0.
   3. The binomial  x-a  factors the polynomial  f%28x%29  if and only if the value of  a  is the root of the polynomial  f%28x%29,  i.e.  f%28a%29+=+0.


See the lessons
    - Divisibility of polynomial f(x) by binomial x-a and the Remainder theorem
    - Solved problems on the Remainder thoerem
in this site.


Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic
"Divisibility of polynomial f(x) by binomial (x-a). The Remainder theorem".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.