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| Question 1144535:   For the opening night at the Opera House, a total of 1000 tickets were
 sold. Front orchestra seats cost $80 apiece, rear orchestra seats cost $60
 apiece, and front balcony seats cost $50 apiece. The combined number of
 tickets sold for the front orchestra and rear orchestra exceeded twice the
 number of front balcony tickets sold by 400. The total receipts for the
 performance were $62,800. Determine how many tickets of each type were
 sold?
 Answer by ankor@dixie-net.com(22740)
      (Show Source): 
You can put this solution on YOUR website! For the opening night at the Opera House, a total of 1000 tickets were sold. Front orchestra seats cost $80 apiece, rear orchestra seats cost $60 apiece, and front balcony seats cost $50 apiece.
 The combined number of tickets sold for the front orchestra and rear orchestra exceeded twice the number of front balcony tickets sold by 400.
 The total receipts for the performance were $62,800.
 Determine how many tickets of each type were sold?
 :
 let a = no. of front orches seats
 let b = no. of rear orches seats
 let c = no. of front balcony seats
 :
 Write an equation for each statement
 :
 "For the opening night at the Opera House, a total of 1000 tickets were sold."
 a + b + c = 1000
 " The total receipts for the performance were $62,800. "
 80a + 60b + 50c = 62800
 :
 "The combined number of tickets sold for the front orchestra and rear orchestra exceeded twice the number of front balcony tickets sold by 400. "
 a + b = 2c + 400
 a + b - 2c = 400
 :
 use elimination on these two equation
 a + b + c = 1000
 a + b - 2c = 400
 ------------------subtraction eliminates a & b, find c
 0 + 0 + 3c = 600
 c = 600/3
 c = 200 front balcony seats
 :
 form two 2 unknown equations with c = 200
 a + b + 200 = 1000
 a + b = 800
 and
 80a + 60b + 50(200) = 62500
 80a + 60b + 10000 = 62500
 80a + 60b = 52800
 multiply the 1st equation by 60, subtract from the above equation
 80a + 60b = 52800
 60a + 60b = 48000
 ------------------- subtraction eliminates b, find a
 20a + 0 = 4800
 a = 4800/20
 a = 240 front orches seats
 Then
 240 + b + 200 = 1000
 b = 1000 - 440
 b = 560 rear orches seats
 :
 :
 Check this on your calc
 80(240) + 60(560) + 50(200) = 62800
 
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