SOLUTION: the positive integers are written in order starting with 1: 1-2-3-4-5-6-7-8-9-1-0-1-1-1-2-1-3-1-4-1-5-1-6-1-7-1-8-1-9-2-0-2-1-2-2-2-3-2-4-2-5-2-6-2-7-2-8. . . What digit is in

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Question 1144185: the positive integers are written in order starting with 1:
1-2-3-4-5-6-7-8-9-1-0-1-1-1-2-1-3-1-4-1-5-1-6-1-7-1-8-1-9-2-0-2-1-2-2-2-3-2-4-2-5-2-6-2-7-2-8. . .
What digit is in the 5000th position?
A)-1
B)-2
C)-5
D)-6
Answer by ikleyn(52800) (Show Source):
You can put this solution on YOUR website!
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There are 9 one-digit numbers from 1 to 9 inclusively : 9 digits, in all. There are 90 two-digit numbers from 10 to 99 inclusively : 180 digits, in all. There are 900 three-digit numbers from 100 to 999 inclusively : 2700 digits, in all. Thus, 9 + 180 + 2700 = 2889 places are just occupied by one-digit, two-digits and three-digits numbers. Starting from the position 2890, the four-digit are placed, each occupies 4 position. Between 5000-th position and 2890-th position, there are about =527.75, and more precisely, 527 four-digit numbers from 1000 to 1526, inclusively. The next number is 1527, giving its third digit " 2 " at the 5000-th position. ANSWER. The digit " 2 " is at 5000-th position.