SOLUTION: 2sin(3x)cos(3x)(2cos^2 3x-1)

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Question 1144138: 2sin(3x)cos(3x)(2cos^2 3x-1)
Answer by ikleyn(52932) About Me  (Show Source):
You can put this solution on YOUR website!
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The product of the first three factors (terms) is


    2*sin(3x)*cos(3x) = sin(6x).


The fourth term is


    2*cos^2(3x)-1 = cos(6x).


Therefore


    2*sin(3x)*cos(3x)*(2cos^2 3x-1) = sin(6x)*cos(6x) = (1/2)*sin(12x).    ANSWER

Solved.