SOLUTION: Two cars leave towns 800 kilometers apart at the same time and travel toward each other. One cars rate is 10 kilometers per hour less than the others . If they meet 5 hours what is
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Question 1144018: Two cars leave towns 800 kilometers apart at the same time and travel toward each other. One cars rate is 10 kilometers per hour less than the others . If they meet 5 hours what is the rate of the slower car? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39618) (Show Source):
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Two cars leave towns 800 kilometers apart at the same time and travel toward each other. One cars rate is 10 kilometers per hour less than the others . If they meet 5 hours what is the rate of the slower car?
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Two cars leave towns D kilometers apart at the same time and travel toward each other. One cars rate is k kilometers per hour less than the others . If they meet t hours what is the rate of the slower car?
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The two speeds are r and r+k.
r+k is the faster car speed, and r is the slow car speed.
The two cars moving toward each other are consuming the D distance until they meet.
Simplify this if you want. Substitute the given values at any time.
Let x be the speed of the slower car, in kilometers per hour.
Then the speed of the faster car is (x+10) kilometers per hour.
In 5 hours, the slower car covers the distance of 5x kilometers, while the faster car covers the distance of 5*(x+10) kilometers.
The sum of the distances is 800 kilometers:
5x + 5*(x+10) = 800.
It is your basic equation.
To solve it, simplify and solve for x.
5x + 5x + 50 = 800
10x = 800 - 50
10x = 750
x = = 75.
ANSWER. The slower car speed is 75 km/h. The faster car speed is 75+10 = 85 km/h.
CHECK. 5*75 + 5*85 = 800 kilometers. ! Correct !
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