SOLUTION: The probability of A’s winning a game of chess against B is 1/3. What is the probability that A will win at least two of a total of 3 games?
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Question 1143766: The probability of A’s winning a game of chess against B is 1/3. What is the probability that A will win at least two of a total of 3 games? Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! Use the Binomial Probability formula,
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Probability(P) (k successes in n trials) nCk * p^(k) * (1-p)^(n-k), where nCk = n!/(k! * (n-k)!)
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P(A will win at least 2 of 3 games) = P(k = 2 in 3 trials) + P(k = 3 in 3 trials) =
:
0.218 + 0.036 = 0.254 is approximately 0.25
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Probability A will win at least 2 of 3 games is 0.25
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