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At given context, those two persons who are to sit next to each other, represent one object with 2 states.
So, the problem is about circular permutations of 7 objects, where one fixed object can be in one of the two states.
The number of circular permutations then is
= 2*6! = 2*6*5*4*3*2*1 = 1440. ANSWER
The factor "2" accounts for the order AB or BA of the two selected persons sitting next to each other.
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On circular permutations, see the lesson
- Persons sitting around a cicular table
in this site.