SOLUTION: One piece of ash was ejected from a volcano with a initial velocity of 336ft/sec. The heigh H in feet is given by the equation H=-16t^2+336t where T is the time in seconds.
When d
Question 1143733: One piece of ash was ejected from a volcano with a initial velocity of 336ft/sec. The heigh H in feet is given by the equation H=-16t^2+336t where T is the time in seconds.
When does the ash projectile reach its maximim height?
What is its maximum height?
when does the ash projectile return to the ground? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! One piece of ash was ejected from a volcano with a initial velocity of 336ft/sec. The heigh H in feet is given by the equation H=-16t^2+336t where T is the time in seconds.
When does the ash projectile reach its maximim height?
It's the vertex of the parabola at t = -b/2a
Solve for t
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What is its maximum height?
Sub t at the vertex.
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when does the ash projectile return to the ground?
When -16t^2 + 336t = 0
Which is 2 times the t at the vertex.
