Question 1143699: In how many ways can letters be chosen from {J,K,L,M,N,O,P,Q,R,S} assuming that the order of the choices doesn't matter and that repeats are not allowed?
Answer by ikleyn(52898) (Show Source):
You can put this solution on YOUR website! .
There are 10 letters in the set, in all, and they all are distinct.
You can select first letter by 10 ways.
Then you can select the second letter by 9 ways among the 9 remaining letters.
Then you can select the second letter by 8 ways among the 8 remaining letters.
. . . and so on . . .
Then you can select the 9-th letter by 2 ways among the 2 remaining letters.
Then you can select the last, 10-th letter by only 1 way among the 1 remaining letter
(practically, you just have no selection choice at this step).
In all, there are 10! = 10*9*8*7* . . . *2*1 = 7257600 ways/selections. ANSWER
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This problem is about PERMUTATIONS.
On permutations, see the introductory lessons
- Introduction to Permutations
- PROOF of the formula on the number of Permutations
- Problems on Permutations
- OVERVIEW of lessons on Permutations and Combinations
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.
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