Question 1143699:  In how many ways can  letters be chosen from {J,K,L,M,N,O,P,Q,R,S} assuming that the order of the choices doesn't matter and that repeats are not allowed? 
 Answer by ikleyn(52903)      (Show Source): 
You can  put this solution on YOUR website! . 
There are 10 letters in the set, in all, and they all are distinct.
You can select first letter by 10 ways.
Then you can select the second letter by 9 ways among the 9 remaining letters.
Then you can select the second letter by 8 ways among the 8 remaining letters.
    . . .        and   so   on   . . . 
Then you can select the 9-th letter by 2 ways among the 2 remaining letters.
Then you can select the last, 10-th letter by only 1 way among the 1 remaining letter 
    (practically, you just have no selection choice at this step).
In all, there are 10! = 10*9*8*7* . . . *2*1 = 7257600 ways/selections.    ANSWER
 
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This problem is about PERMUTATIONS.
 
 
On permutations, see the introductory lessons
 
    - Introduction to Permutations
 
    - PROOF of the formula on the number of Permutations
 
    - Problems on Permutations
 
 
    - OVERVIEW of lessons on Permutations and Combinations
 
in this site.
 
 
Also,  you have this free of charge online textbook in ALGEBRA-II in this site
 
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.
 
 
The referred lessons are the part of this online textbook under the topic  "Combinatorics: Combinations and permutations". 
 
 
 
Save the link to this textbook together with its description
 
 
Free of charge online textbook in ALGEBRA-II 
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
 
 
into your archive and use when it is needed.
 
 
 
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