SOLUTION: Please kindly help with this questions. solve e^(2x+1) + 9e^x - 11 = 0

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Question 1143609: Please kindly help with this questions.
solve e^(2x+1) + 9e^x - 11 = 0

Answer by ikleyn(52798) About Me  (Show Source):
You can put this solution on YOUR website!
.

    e%5E%282x%2B1%29+%2B+9e%5Ex+-+11 = 0      (1)


    e%2Ae%5E%282x%29+%2B+9%2Ae%5Ex+-+11 = 0      (2)


Introduce new variable t = e^x.

Then the equation (2)  takes the form


     e%2At%5E2+%2B+9t+-+11 = 0.       (3)


Apply the quadratic formula


     t = %28-9+%2B-+sqrt%289%5E2+-+4%2Ae%2A%28-11%29%29%29%2F%282%2Ae%29 = %28-9+%2B-+sqrt%2881+%2B+44e%29%29%2F%282e%29.


So, the equation (3) has two roots


      t%5B1%5D = %28-9+%2B+sqrt%2881+%2B+44e%29%29%2F%282e%29  and  t%5B2%5D = %28-9+-+sqrt%2881+%2B+44e%29%29%2F%282e%29.


Both the roots  t%5B1%5D  and  t%5B2%5D are real numbers.


Since  t = e%5Ex, we can use ONLY POSITIVE root t%5B1%5D to find x:


    x = ln%28%28-9+%2B+sqrt%2881+%2B+44e%29%29%2F%282e%29%29.      ANSWER


It is the ONLY SOLUTION to the original equation (1).

Solved.

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Introducing new variable is the STANDARD method for solving such equations.

To see other similar solved problems, look into the lesson
    - Solving exponential equations
in this site.