SOLUTION: A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, t

Algebra ->  Customizable Word Problem Solvers  -> Evaluation -> SOLUTION: A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, t      Log On

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Question 1143469: A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, the wind is still blowing at the same speed, so the return trip takes only 1 hour 12 minutes. What is his speed in still air, and how fast is the wind blowing?

Your answer is
his speed equals

the wind speed equals

Answer by ikleyn(52772) About Me  (Show Source):
You can put this solution on YOUR website!
.

            You formatted your post as if you want to say
              "I do not want to know the method of the solution - I want the answer only".

            Therefore, I will put the solution in shortest form, without wording comments.


    u - v = 180%2F2 = 90            

    u + v = 180%2F%28%286%2F5%29%29 = 150     



    u - v = 90

    u + v = 150


==================>


    2u = 90+150 = 240  ====>  u = 240/2 = 120 mph.     the speed of the plane at no wind, mph

     v = 150 - 120 = 30.                               the wind speed, mph

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