SOLUTION: The mean lifetime of a tire is 43 months with a standard deviation of 10
months.
If 105
tires are sampled, what is the probability that the mean of the sample would differ
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-> SOLUTION: The mean lifetime of a tire is 43 months with a standard deviation of 10
months.
If 105
tires are sampled, what is the probability that the mean of the sample would differ
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Question 1143460: The mean lifetime of a tire is 43 months with a standard deviation of 10
months.
If 105
tires are sampled, what is the probability that the mean of the sample would differ from the population mean by less than 0.41 months? Round your answer to four decimal places. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! z=(x-mean)/sigma/sqrt(n)
z interval has to be 0.41/(10/sqrt(105)) or 0.41*sqrt(105)/10 or 0.42
therefore z is constrained to be between -0.42 and +0.42
The probability z is between those two values, -0.42 and +0.42, is 0.3255
