Question 1143458: In baseball, a batting average is the probability of the number of hits divided by the number of times at bat. A batting average over 0.300 is very good. This means that a player will get a hit 300 times for every 1000 times at bat. So, assume the probability of getting a hit is 0.368 for each time a player is at bat. In a particular game, assume the batter batted three times.
A) What is the probability of getting three hits in a particular game?
B) What is the probability of not getting any hits in a game? (Round the final answer to 3 decimal places.)
C) What is the probability of getting at least one hit? (Round the final answer to 3 decimal places.) Probability
Found 2 solutions by greenestamps, Alan3354:
Answer by greenestamps(13200)   (Show Source):
You can put this solution on YOUR website!
P(0 hits) = C(3,0)*(.368^0)*(1-.368)^3
P(1 hit) = C(3,1)*(.368^1)*(1-.368)^2
P(2 hits) = C(3,2)*(.368)^2*(1-.368)^1
P(3 hits) = C(3,3)*(.368)^3*(1-.368)^0
The answers to parts A and B are in the above calculations.
For part C, you can either add the probabilities for 1, 2, and 3 hits, or you can just do 1 minus the probability of 0 hits.
Answer by Alan3354(69443)  (Show Source):
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