SOLUTION: What is the equation, in slope-intercept form, of the line that is perpendicular to the line y - 4 = - (x - 6) and passes through the point (−2, −2)? y = - x -

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Question 1143408: What is the equation, in slope-intercept form, of the line that is perpendicular to the line
y - 4 = - (x - 6) and passes through the point (−2, −2)?
y = - x - y = - x +
y = x - 1
y = x + 1
Found 2 solutions by Alan3354, Edwin McCravy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
What is the equation, in slope-intercept form, of the line that is perpendicular to the line
y - 4 = - (x - 6) and passes through the point (−2, −2)?
==============================
----> y = -x + some constant, slope = -1
Lines perpendicular have a slope that's the negative reciprocal.
-(1/-1) = 1
m = 1
------
y - y1 = m*(x - x1) where (x1,y1) is the point (-2,-2)
y + 2 = 1*(x+2)
y = x
===================
y = 1x + 0

Answer by Edwin McCravy(20064) About Me  (Show Source):
You can put this solution on YOUR website!
y+-+4+=+-%28x+-+6%29
Since 
y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29 has slope m, and since
y+-+4+=+-%28x+-+6%29 is equivalent to
y+-+4+=+-1%28x+-+6%29, then m = -1 the slope of the given line.
The slope of a line perpendicular to a line with slope m is -1%2Fm.
So the line we want has slope -1%2F%28-1%29 or 1
y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29
we substitute (x1, y1) = (-2, -2) and m = 1:
y+-+%28-2%29+=+1%28x+-+%28-2%29%5E%22%22%29
y+%2B+2+=+x+%2B+2
Subtract 2 from each side:
y=x

Below the red line is the given line y+-+4+=+-%28x+-+6%29
and the green line is the one we found y=x

graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C-x%2B10%2Cx%29

Edwin