SOLUTION: How to solve for x the following 3x(2x-1)=0 2x^2+x=4

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Question 1143371: How to solve for x the following
3x(2x-1)=0
2x^2+x=4

Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
Two equations, not of a system
Simple algebra to solve


3x%282x-1%29=0
Either x is 0 or 2x-1 is 0;
Go on from there.


2x%5E2%2Bx=4
How do you want? Simple arithmetic knowledge or simple algebra?
x%282x%2B1%29=4-----will this be enough?
or
2x%5E2%2Bx-4=0
x=%28-1%2B-+sqrt%281%5E2%2B4%2A2%2A4%29%29%2F%284%29
x=%28-1%2B-+sqrt%2833%29%29%2F4