SOLUTION: if a drink contains 67% juice concentrate and drink b contains 7%. how much of a solution should be mixed in order to create 150 liters of a solution that contains 47% juice concen

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Question 1143346: if a drink contains 67% juice concentrate and drink b contains 7%. how much of a solution should be mixed in order to create 150 liters of a solution that contains 47% juice concentrate.
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
system%28a%2Bb=150%2C67%2Aa%2B7b=47%2A150%29

67a%2B7%28150-a%29=47%2A150----------solve first for a.
--
67a%2B7%2A150-7a=47%2A150
%2867a-7a%29%2B7%2A150=47%2A150
%2867-7%29a=47%2A150-7%2A150
%2867-7%29a=150%2847-7%29
highlight_green%28a=150%28%2847-7%29%2F%2867-7%29%29%29
or more simplified
highlight_green%28a=150%282%2F3%29%29----------volume liters of the 67% juice concentrate

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Picture the three percentages on a number line: 7, 47, and 67.

Perform calculations to show that 47 is 2/3 of the way from 7 to 67.

That means 2/3 of the mixture must be the 67% juice.

ANSWER: 2/3 of 150 liters, or 100 liters, of 67% juice; the other 50 liters of 7% juice.

CHECK:
100(.67)+50(.07) = 67+3.5 = 70.5
150(.47) = 70.5