SOLUTION: The distance covered by a stone is inversely proportional to square of its weight. A 3 kg stone covers a distance of 9 meter when it is thrown. What will be the distance covered

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Question 1143343: The distance covered by a stone is inversely proportional to square of its weight.
A 3 kg stone covers a distance of 9 meter when it is thrown. What will be the
distance covered by a 4 kg stone when it is thrown?

Found 3 solutions by josmiceli, greenestamps, ikleyn:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+d+=+k%2A%281%2Fw%29%5E2+
+d+=+9+ m
+w+=+3+ kg
+9+=+k%2A%28+1%2F3+%29%5E2+
+9+=+k%2A%28+1%2F9+%29+
+k+=+81+
----------------------
+w+=+4+ kg
+d+=+81%2A%28+1%2F4+%29%5E2+
+d+=+81%2F16+
+d+=+5.0625+ m

Answer by greenestamps(13209) About Me  (Show Source):
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The ratio of the weights of the new and old stones is 4/3. Since the distance covered is inversely proportional to the square of the weight, the distance covered by the new stone is 1%2F%28%284%2F3%29%5E2%29 = 1%2F%2816%2F9%29 = 9%2F16 of the distance of the old stone.

ANSWER: (9/16) of 9 meters = 81/16 meters

Answer by ikleyn(52887) About Me  (Show Source):
You can put this solution on YOUR website!
.
The person who created this formulation, deserves lowest possible score for his ability (or, better to say, inability)
to formulate the problem correctly and, in addition to it, deserves lowest possible score for total absence
base knowledge in Mechanics.

Why ?

First, because the context is not disclosed: what are the conditions for such an experiment ?

How the first sentence is formulated, one can conclude that a free fall of the body is considered.

    Although the word "thrown" in the next sentence contradicts to it.

Second, from the times of Galileo (~ 1600 years) it is known that the distance covered by a free falling body
DOES  NOT  DEPEND  on its weight.


It is one of the corner stones in Mechanics.