SOLUTION: Khalid loses 1/3rd of his money in the first game, 3.5ths of the remainder in the second and 4/7ths of the rest in the third. Thus he is left with . . . . .. ths of his money:
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Question 1143317: Khalid loses 1/3rd of his money in the first game, 3.5ths of the remainder in the second and 4/7ths of the rest in the third. Thus he is left with . . . . .. ths of his money: Found 3 solutions by Theo, MathTherapy, Alan3354:Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! he loses 1/3 in the first game.
1/3 * 1 = 1/3
he is left with 1 - 1/3 = 2/3 * his original money.
he loses 3/5 * what he is left with from the first game in the second game.
3/5 * 2/3 = 6/15.
he is left with 2/3 - 6/15 = 10/15 - 6/15 = 4/15 * his original money.
he loses 4/7 of what he is left with from the second game in the third game.
4/7 * 4/15 = 16/105.
he is left with 4/15 - 16/105 = 28/105 - 16/105 = 12/105 of his original money.
that should be your solution.
he is left with 12/105 of his original money.
let's see if this is correct.
assume that he started with 12000 dollars.
he loses 1/3 of 12000 = 4000.
he is left with 8000.
he then loses 3/5 * 8000 = 4800.
he is left with 8000 - 4800 = 3200.
he then loses 4/7 * 3200 = 1828.571428571
he is left with 3200 - 1818.571428571 = 1371.428571429
You can put this solution on YOUR website!
Khalid loses 1/3rd of his money in the first game, 3.5ths of the remainder in the second and 4/7ths of the rest in the third. Thus he is left with . . . . .. ths of his money:
You can put this solution on YOUR website! Khalid loses 1/3rd of his money in the first game, 3.5ths of the remainder in the second and 4/7ths
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It's not 1/3rd, it's 1/3. That's one third, 1/3.
Same for 4/7 = four sevenths - not 4/7ths.
IDK what 3.5ths might mean.