SOLUTION: Find an equation of the line satisfying the given conditions. Through (-6,7); parallel to 3x+7y=3

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Question 1143191: Find an equation of the line satisfying the given conditions. Through (-6,7); parallel to 3x+7y=3
Found 2 solutions by Boreal, greenestamps:
Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website!
3x+7y=3
7y=-3x+3
y=-(3/7)x+ (3/7)
slope of that line is -3/7
point slope formula y-y1=m(x-x1), m slope and (x1, y1) point
y-7=(-3/7)(x+6)
y=(-3x/7)-18/7+49/7
y=(-3x/7)+31/7

Answer by greenestamps(13200) (Show Source):
You can put this solution on YOUR website!

Every line parallel to 3x+7y=3 will have an equation of the form 3x+7y=c for some constant c.

To find the equation of the line parallel to 3x+7y=3 containing a specific point (x,y), simply substitute those values...

3x+7y = 3(-6)+7(7)
3x+7y = -18+49
3x+7y = 31