Question 1143163: A simple random sample of 37 men from a normally distributed population results in a standard deviation of 8.5 beats per minute. The normal range is 60-100 beats per minute. If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute. Use the sample results with a 0.10 significance level to test the claim that pulse rates of me. Have a standard deviation equal to 10 beats per minute. Find the test statistic and P value.
I know that the test statistic x^2 = 26.01 and P value is 0.2196 because it showed me the answer after I got it wrong. How do I find the P value? I could do it with questions where I know the answer of t or the z score. But I cannot figure out how to find the p value with x^2. Please please help!! Thank you in advance to anyone who does. I’ve done so much research and trying to figure it out. I’m lost.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! If one uses a calculator with Chi-Sq, the arguments are (0, 26.01, 36). That gives a value of 0.1098. That is for a one way test. For a two way test (equal or not) one doubles that value, and that is where the 0.2196 comes from.
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