SOLUTION: Assume that the heights of women are normally distributed with a mean of 62.2 inches and a
standard deviation of 2.3 inches. Find Q3, the third quartile that separates the bottom
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-> SOLUTION: Assume that the heights of women are normally distributed with a mean of 62.2 inches and a
standard deviation of 2.3 inches. Find Q3, the third quartile that separates the bottom
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Question 1143061: Assume that the heights of women are normally distributed with a mean of 62.2 inches and a
standard deviation of 2.3 inches. Find Q3, the third quartile that separates the bottom 75% from the
top 25%. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! z for the third quartile or 0.7500 is -0.67
z=(x-mean)/sd
0.67=(x-62.2)/2.3
1.55=x-62.2
x=63.75 inches
