SOLUTION: Statistics
A human gene carries a certain disease from the mother to the child with a probability rate of forty percent (40%). That is, there is a 40% chance that the child bec
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A human gene carries a certain disease from the mother to the child with a probability rate of forty percent (40%). That is, there is a 40% chance that the child bec
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Question 1143042: Statistics
A human gene carries a certain disease from the mother to the child with a probability rate of forty percent (40%). That is, there is a 40% chance that the child becomes infected with the disease. Suppose a female carrier of the gene has three children. Assume that the infections of the three children are independent of one another. Find the probability that at least one of the children get the disease from their mother.
a. 0.216
b. 0.784
c. 0.432
d. 0.144 Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Find the probability than none get the disease. That is 0.6^3=0.216
The probability of at least 1 is 1 minus the probability none got it or 1-0.216=0.784.
B.
This is easier than doing the probability of 1 or 2 or all 3.
