SOLUTION: if X^2+Y^2+Z^2=2(5X-8Y+6Z)-125 THEN FIND THE VALUE OF X+Y+Z IS?

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Question 1143017: if X^2+Y^2+Z^2=2(5X-8Y+6Z)-125 THEN FIND THE VALUE OF X+Y+Z IS?
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
X%5E2+%2B+Y%5E2+%2B+Z%5E2+=+2%285X+-+8Y+%2B+6Z%29+-+125
X%5E2+%2B+Y%5E2+%2B+Z%5E2+=+10X+-+16Y+%2B+12Z+-+125
X%5E2-10X+%2B+Y%5E2%2B16Y+%2B+Z%5E2-12Z+=+-125
%28X%5E2-10X%29+%2B+%28Y%5E2%2B16Y%29+%2B+%28Z%5E2-12Z%29+=+-125

Complete the square in each parentheses by adding the 
square of half the coefficient of X, Y and Z respectively 
inside each parentheses on the left side of the equation, 
and adding the same quantities to the right side.

%28X%5E2-10X%2B25%29%2B%28Y%5E2%2B16Y%2B64%29%2B%28Z%5E2-12Z%2B36%29=-125%2B25%2B64%2B36

Factor each parenthetical expression as a perfect square
and combine the terms on the right:

%28X+-+5%29%5E2+%2B+%28Y+%2B+8%29%5E2+%2B+%28Z+-+6%29%5E2+=+0

That's the equation of a sphere with center (5,-8,6) and
radius 0.   So it is the equation of a sphere that is 
degenerated into the point (5,-8,6) in 3D space.

X = 5, Y = -8, Z = 6, So X+Y+Z = 5-8+6 = 3

Edwin