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Question 1142826: What is the standard equation of the circle which has (-1,3) and (2,4) as the end points of a diameter
I followed a YouTube tutorial and want to make sure that I am right
So I used the midpoint formula (-1+3)/2,(2+4)/2= (1,3)
Then I used the formula for finding the radius r=1/2squareroot of (2-(-1)^2+(4-3)^2 I evualated it then got squareoot of 5/2
And r^2=(5/2)^2 = 5/4
And I got the standard equation (x-1)^2+(y-3)^2= 5/4
Answer by greenestamps(13203)   (Show Source):
You can put this solution on YOUR website!
Your midpoint and radius are both incorrect.
The midpoint formula finds the x coordinate of the midpoint as the average of the x coordinates of the two endpoints and the y coordinate of the midpoint as the average of the y coordinates of the two endpoints. You didn't do that.
The calculation you show for the radius is correct; but you didn't evaluate it correctly.
Look at your work again and see if you can correct your errors; post a "thank you" note if you need more help, explaining or demonstrating what it is you need help with.
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