SOLUTION: Find the integral of e^(logx). The solutions gave the answer as x^2/2 +c, but I'm prety sure that logx is not the same as lnx ??

Algebra ->  Expressions -> SOLUTION: Find the integral of e^(logx). The solutions gave the answer as x^2/2 +c, but I'm prety sure that logx is not the same as lnx ??      Log On


   

Question 1142776: Find the integral of e^(logx).
The solutions gave the answer as x^2/2 +c, but I'm prety sure that logx is not the same as lnx ??
Answer by ikleyn(52841) About Me  (Show Source):
You can put this solution on YOUR website!
.

Notice that  e%5E%28ln%28x%29%29 = x  BY THE DEFINITION of (the natural) logarithm.


Therefore, 


    integral of  e%5E%28ln%28x%29%29%2Adx = integral of  x*dx = x%5E2%2F2 + c.