SOLUTION: the sum of three consecutive numbers is 117.find the biggest number.

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Question 1142745: the sum of three consecutive numbers is 117.find the biggest number.
Found 2 solutions by ankor@dixie-net.com, Alan3354:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
n, (n-1), (n-2) are the three numbers
:
the sum of three consecutive numbers is 117.
n + (n-1) + (n-2) = 117
3n - 3 = 117
3n = 117 + 3
3n = 120
n = 120/3
n = 40 is the biggest number.
:
:
Check: 40 + 39 + 38 = 117

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of 3 consecutive numbers is always 3 times the middle number.
117/3 = 39
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This is true of even numbers and for odd numbers, too.
Any number of "equal difference" or the product of any constant.