SOLUTION: Suppose ABCD is a square with side length (x-1) cm. If the area of rectangle ABFE is (x^2+x-2)cm^2 then the length of FC in cm, is

Algebra ->  Expressions-with-variables -> SOLUTION: Suppose ABCD is a square with side length (x-1) cm. If the area of rectangle ABFE is (x^2+x-2)cm^2 then the length of FC in cm, is       Log On


   

Question 1142743: Suppose ABCD is a square with side length (x-1) cm. If the area of rectangle ABFE is (x^2+x-2)cm^2 then the length of FC in cm, is
Answer by solver91311(24713) About Me  (Show Source):
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If the side length of ABCD is , then the area of ABCD is .

The difference in the area of rectangle ABFE and square ABCD is , and this is the area of rectangle DCFE.

One side of rectangle DCFE, namely DC, must have length ,
so either side orthogonal to side DC, one of which is side CF, must have a measure of:




John

My calculator said it, I believe it, that settles it