SOLUTION: you throw a softball straight up into the air at a velocity of 30 feet per second. You release the softball at a height of 5.8 feet and catch it when it falls back to a height of 6

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: you throw a softball straight up into the air at a velocity of 30 feet per second. You release the softball at a height of 5.8 feet and catch it when it falls back to a height of 6      Log On

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Question 1142700: you throw a softball straight up into the air at a velocity of 30 feet per second. You release the softball at a height of 5.8 feet and catch it when it falls back to a height of 6.2 feet. Use the position equation to write a mathematical model for the height of the softball
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
The position equation is


    h(t) = -16*t^2 + v*t + h%5B0%5D,


where t is the time in seconds;  h(t) is the height over the ground level, in feet;

v is the initial vertical velocity, in ft/s;  and h%5B0%5D is the initial height, in feet.


So, in your case, the position equation is


    h(t) = -16*t^2 + 30*t + 5.8.