SOLUTION: Find the point P such that {{{AP/AB =r}}} A = (4,-2), B=(-2,-5) {{{r = 2/3}}} I get (0,-4). Thank you.

Algebra ->  Length-and-distance -> SOLUTION: Find the point P such that {{{AP/AB =r}}} A = (4,-2), B=(-2,-5) {{{r = 2/3}}} I get (0,-4). Thank you.      Log On


   

Question 1142686: Find the point P such that AP%2FAB+=r
A = (4,-2), B=(-2,-5) r+=+2%2F3
I get (0,-4). Thank you.
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


You want P to be 2/3 of the way from A to B.

When that is true, the x coefficient of P will be 2/3 of the way from the x coefficient of A to the x coefficient of B, and likewise for the y coefficient of P.

The x coefficients of A and B are 4 and -2, a difference of -6; 2/3 of -6 is -4; the x coefficient of P is 4+(-4) = 0.

The y coefficients of A and B are -2 and -5, a difference of -3; 2/3 of -3 is -2; the y coefficient of P is -2+(-2) = -4.

The point P is P(0,-4).

Your answer is correct.

However, if you used a method from a textbook or some similar resource which uses some sort of mathematical formulas, chances are the work you did to get the answer was more than what I did with my informal common sense approach....