SOLUTION: Find the z-score boundaries that separate a normal distribution as described in each of the following.
The middle 30% from the 70% in the tails.
The middle 42% from the 58%
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-> SOLUTION: Find the z-score boundaries that separate a normal distribution as described in each of the following.
The middle 30% from the 70% in the tails.
The middle 42% from the 58%
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Question 1142646: Find the z-score boundaries that separate a normal distribution as described in each of the following.
The middle 30% from the 70% in the tails.
The middle 42% from the 58% in the tails. Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! if 70% is in the tails, then half of that is in the left tail and half of that is in the right tail.
if you find the z-score for the left tail, then the same z-score with the opposite sign will be the z-score for the right tail.
specifically.
30% is in the middle which means 70% / 2 = 35% is in the left tail.
you look for a z-score that has .35 of the area under the normal distribution curve to the left of it.
that z-score will be -.385 rounded to 3 decimal places.
that will be the low z-score.
the high z-score will be +.385 rounded to 3 decimal places.
