SOLUTION: A man sets two goals for himself in the year 2018,he intends to marry with a probability of 3/4 and he buys a new car with the probability of 3/7. What is the probability that he a

Algebra ->  Probability-and-statistics -> SOLUTION: A man sets two goals for himself in the year 2018,he intends to marry with a probability of 3/4 and he buys a new car with the probability of 3/7. What is the probability that he a      Log On


   

Question 1142499: A man sets two goals for himself in the year 2018,he intends to marry with a probability of 3/4 and he buys a new car with the probability of 3/7. What is the probability that he achieve the two goals
Answer by ikleyn(52925) About Me  (Show Source):
You can put this solution on YOUR website!
.

If to assume that these two events are INDEPENDENT, then the probability that both events will happen is the product 

of individual/partial probabilities


    P = 3%2F4.3%2F7 = 9%2F28.


Without such assumption, the problem can not be solved, at all.


But validity of the assumption itself is questionable, in real life.

---------------

Let me tell you slightly more about this problem.

Behind each probability problem,  there is,  actually,  an experiment.

At least,  a  MENTAL  experiment.

Now,  could you imagine any real life experiment behind  THIS  problem ?


It is why this problem can be considered as a joke  ONLY :   ONLY  in its  joking mode.