SOLUTION: In a factory,three machines,A,B and C, are used to manufacture plastic bottles.they produce 20%,30% and 50% respectively of the total production.1%,2%and 6% respectively of the pla
Algebra ->
Probability-and-statistics
-> SOLUTION: In a factory,three machines,A,B and C, are used to manufacture plastic bottles.they produce 20%,30% and 50% respectively of the total production.1%,2%and 6% respectively of the pla
Log On
Question 1142494: In a factory,three machines,A,B and C, are used to manufacture plastic bottles.they produce 20%,30% and 50% respectively of the total production.1%,2%and 6% respectively of the plastic bottles produced by machines A,B and C defective.
6.1 Represent the information by means of a tree diagram.clearly indicate the probability associated with each branch of the tree diagram and write down all the outcomes.
6.2 A plastic bottle is selected at random from the total production.
(a) What is the probability that it was produced by machine B and it is not defective?
(b) What is the probability that the bottle is defective?
Can I get help with this please Answer by greenestamps(13203) (Show Source):
6.1 Sorry... tree diagrams don't work very well in typed text. You can do that part.
A1: machine A and defective: 0.20*0.01 = 0.0020
A2: machine A and not defective: 0.20*0.99 = 0.1980
B1: machine B and defective: 0.30*0.02 = 0.0060
B2: machine B and not defective: 0.30*0.98 = 0.2940
C1: machine C and defective: 0.50*0.06 = 0.0300
C2: machine C and not defective: 0.50*0.94 = 0.4700
---------
1.0000
