Differentiate with respect to x : y=3-2x/(1+x)^2. Simplifying your answer.
==============
I would use u-substitution (first easy method I see, may be other ways):
Let u = 1+x ==> du/dx = 1
x = u-1 ==> 2x = 2u-2
dy/dx = (dy/du)(du/dx)
Writing y in terms of u:
Since du/dx = 1, we just need to re-write the above in terms of x, so substitute back 1+x for u:
=