SOLUTION: PROJECTILE IS LAUNCHED FROM GROUND LEVEL WITH AN INITIAL VELOCITY OF v0 FEET PER SECOND. NEGLECTING AIR RESISTANCE, ITS HEIGHT IN FEET t SECONDS AFTER LAUCH IS GIVEN BY s = -16^2+
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: PROJECTILE IS LAUNCHED FROM GROUND LEVEL WITH AN INITIAL VELOCITY OF v0 FEET PER SECOND. NEGLECTING AIR RESISTANCE, ITS HEIGHT IN FEET t SECONDS AFTER LAUCH IS GIVEN BY s = -16^2+
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Question 1142469: PROJECTILE IS LAUNCHED FROM GROUND LEVEL WITH AN INITIAL VELOCITY OF v0 FEET PER SECOND. NEGLECTING AIR RESISTANCE, ITS HEIGHT IN FEET t SECONDS AFTER LAUCH IS GIVEN BY s = -16^2+ v0t
::: IN NUMBER 25, FIND THE TIME (s) THAT THE PROJECTILE WILL (a)REACH A HEIGHT OF 192ft AND (b) RETURN TO THE GROUND FOR THE GIVEN VALUE OF v0=112fps. ROUND ANSWERS TO THE NEAREST HUNDREDTH IF NECESSARY. Answer by Alan3354(69443) (Show Source):
