Question 1142467: There are 18 red, 15 white, and 12 blue pieces of candy in a bag. What is the probability of selecting 2 blue, 1 red, and 1 white piece, replacing the candy each time?
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! There are 18 red, 15 white, and 12 blue pieces of candy in a bag. What is the probability of selecting 2 blue, 1 red, and 1 white piece, replacing the candy each time?
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IOW, with replacement.
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45 pieces total
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2 blue --> (12/45)*(12/45) = 16/225
1 red ---> 18/45
1 white -> 15/45
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It's the product of those 3 terms.
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