SOLUTION: Please help me solve this: The equation of line l1 is 2y−5x−1 = 0. Line l2 is perpendicular to l1 and passes through (5, −1). The equation of l2 is 1. 5y − 2x + 15 =

Algebra ->  Formulas -> SOLUTION: Please help me solve this: The equation of line l1 is 2y−5x−1 = 0. Line l2 is perpendicular to l1 and passes through (5, −1). The equation of l2 is 1. 5y − 2x + 15 =       Log On


   

Question 1142373: Please help me solve this:
The equation of line l1 is 2y−5x−1 = 0. Line l2 is perpendicular to l1 and passes through (5, −1). The equation of l2 is
1. 5y − 2x + 15 = 0
2. 5y + 2x − 15 = 0
3. 5y + 2x − 5 = 0
4. 5y − 2x + 5 = 0
5. 2y − 5x + 27 = 0
Answer by josgarithmetic(39617) About Me  (Show Source):