SOLUTION: Find all solutions of the equation in the interval [0,2π).
-cosx = -sin^2x-1
Write your answer in radians in terms of π.
If there is more than one solution, separate with c
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-> SOLUTION: Find all solutions of the equation in the interval [0,2π).
-cosx = -sin^2x-1
Write your answer in radians in terms of π.
If there is more than one solution, separate with c
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Question 1142370: Find all solutions of the equation in the interval [0,2π).
-cosx = -sin^2x-1
Write your answer in radians in terms of π.
If there is more than one solution, separate with commas. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Find all solutions of the equation in the interval [0,2π).
-cosx = -sin^2x-1
Add parentheses:
-cos(x) = -sin^2(x) - 1
Is that what you meant?
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cos(x) = sin^2(x) + 1
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Can you do the rest?
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Do NOT say this:
If there is more than one solution, separate with commas.
What would we do if we don't have any commas?
