SOLUTION: The altitude H, in meters of a launched object is given in the polynomial equation h = h to the 0 power + vt - 4.9t to the second power. where H to the zero power is the height, in
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Question 1142318: The altitude H, in meters of a launched object is given in the polynomial equation h = h to the 0 power + vt - 4.9t to the second power. where H to the zero power is the height, in meters, from which the launch occurs, v is the initial upward speed, in meters per second m/s, and t is the number of seconds which the object is airborne.
A model rocket is launched from the top of a building 32 m above the ground. The upward speed is 40 m/s. How high will the rocket be 2 seconds after the blastoff? Answer by ikleyn(52802) (Show Source):
You are given the function for it
h(t) = + vt - .
Substitute the given values = 32 m; v = 40 m/s; and t= 2 seconds into the formula.
You will get the answer IMMEDIATELY.
This instruction should be enough for you, clearly explaining what to do.
Happy calculations !
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