SOLUTION: Suppose that a factory's cost (in dollars) for making x cars is C(x)=5410x+5510 Then the average cost per car is C'(x)=5410x+5510/x How many cars must the factory make each day

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Suppose that a factory's cost (in dollars) for making x cars is C(x)=5410x+5510 Then the average cost per car is C'(x)=5410x+5510/x How many cars must the factory make each day      Log On


   



Question 1142293: Suppose that a factory's cost (in dollars) for making x cars is
C(x)=5410x+5510
Then the average cost per car is
C'(x)=5410x+5510/x
How many cars must the factory make each day to ensure the average cost per car is no more than $5600?

Found 3 solutions by rothauserc, ikleyn, josgarithmetic:
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
(5410x +5510) / x = 5600
:
5410x +5510 = 5600x
:
190x = 5510
:
x = 29
:
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The factory must make at most 29 cars daily
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:

Answer by ikleyn(52921) About Me  (Show Source):
You can put this solution on YOUR website!
.

The solution and the answer by tutor @rothauserc is INCORRECT.

    The correct answer is THIS :  the factory must produce at least 29 cars daily.


    It is absolutely clear for anybody when he (or she) will turn on his (or her) common sense.



Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
%285410x%2B5510%29%2Fx%3C=5600

5410x%2B5510%3C=5600x

5510%3C=190x

29%3C=x
Twenty-nine or more