SOLUTION: {X+1}{x+1}= {W-7}{w-7}= {b+10}{b+10}= {a-a}{a-a}=

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Question 1142005: {X+1}{x+1}=
{W-7}{w-7}=
{b+10}{b+10}=
{a-a}{a-a}=
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
Are those all of a form %28x%2By%29%28x%2By%29 ?
If yes, then use of distributive property and simplification should give the basic result x%5E2%2B2xy%2By%5E2.