Question 1141946: Two numbers sum to 49.
Twice the first subtracted from the second is 7. Find the numbers.
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! a is the first number.
b is the second number.
a + b = 49
b - 2a = 7
solve for b in the second equation to get b = 2a + 7
replace b with 2a + 7 in the first equation to get a + 2a + 7 = 49
combine like terms to get 3a + 7 = 49
subtract 7 from both sides of the equation to get 3a = 42
solve for a to get a = 14
since a + b = 49, then b must be equal to 35.
a + b = 49 becomes 14 + 35 = 49 which becomes 49 = 49 which is true.
b - 2a = 7 becomes 35 - 2 * 14 = 7 which becomes 35 - 28 = 7 which becomes 7 = 7 which is true.
solution looks good.
solution is the first number = 14 and the second number = 35.
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