SOLUTION: Two buses leave towns 580 miles
apart at the same time and travel toward each other. One bus travels 19 mi/h
slower than the other. If they meet in 4
hours, what is the
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-> SOLUTION: Two buses leave towns 580 miles
apart at the same time and travel toward each other. One bus travels 19 mi/h
slower than the other. If they meet in 4
hours, what is the
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Question 1141934: Two buses leave towns 580 miles
apart at the same time and travel toward each other. One bus travels 19 mi/h
slower than the other. If they meet in 4
hours, what is the rate of each bus? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = the speed of the faster bus = the speed of the slower bus
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This is the same as if one of the buses travels at
the sum of their speeds for the entire distance, so
and
The speed of the faster bus is 82 mi/hr
The speed of the slower bus is 63 mi/hr
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check:
and
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OK
