SOLUTION: Given P(A)=0.27, P(B)=0.72, and P(A∩B)=0.11, what is P(A^c ∩B)?

Algebra ->  Probability-and-statistics -> SOLUTION: Given P(A)=0.27, P(B)=0.72, and P(A∩B)=0.11, what is P(A^c ∩B)?      Log On


   



Question 1141769: Given P(A)=0.27, P(B)=0.72, and P(A∩B)=0.11, what is P(A^c ∩B)?
Answer by ikleyn(52921) About Me  (Show Source):
You can put this solution on YOUR website!
.

(A^c ∩ B)  is the part of B which is not A.


So,    (A^c ∩ B)  = B \ (A ∩ B).


Therefore,  P(A^c ∩ B) = P(B) - P(A ∩ B) = 0.72 - 0.11 = 0.61.     ANSWER

Completed and solved.