SOLUTION: The perimeter of a rectangle is 22 in. If the length is one more than the width, what is the area of the rectangle, a square inches?

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Question 1141729: The perimeter of a rectangle is 22 in. If the length is one more than the width, what is the area of the rectangle, a square inches?
Found 2 solutions by Boreal, MathLover1:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x is length
x-1 is width
x+(x-1)=11, the half-perimeter is one length plus one width
2x=12
x=6 inches length
5 inches with
area is 30 in^2.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

The perimeter of a rectangle is 22in.
P=2%28L%2BW%29
=>2%28L%2BW%29=22in
=>L%2BW=22in%2F2
=>L%2BW=11in........eq.1

If the length L is one more than the width W, we have
L=W%2B1in....eq.2

substitute it in eq.1
W%2B1in%2BW=11in........eq.1....solve for W
2W=11in-1in
2W=10in
W=+5in

go to eq.2, substitute W

L=W%2B1in....eq.2
L=5in%2B1in
L=6in

now find the area:

A=L%2AW
A=6in%2A5in
A=30in%5E2