SOLUTION: The vertices of a triangle ABC A(2,4) B(-2,0) and C(6,-1). (a) Find the coordinate of the midpoint P, Q, R of the sides AB, BC and CA respectively. (b) Find the equation of the m

Algebra ->  Equations -> SOLUTION: The vertices of a triangle ABC A(2,4) B(-2,0) and C(6,-1). (a) Find the coordinate of the midpoint P, Q, R of the sides AB, BC and CA respectively. (b) Find the equation of the m      Log On


   



Question 1141667: The vertices of a triangle ABC A(2,4) B(-2,0) and C(6,-1).
(a) Find the coordinate of the midpoint P, Q, R of the sides AB, BC and CA respectively.
(b) Find the equation of the medians AQ and BR, and the coordinates of the point were they intersect.
(c) Show that the third median CP also passes through this point

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

given:
The vertices of a triangle ABC
A(2,4)
B(-2,0)
C(6,-1)

(a) Find the coordinate of the midpoint P, Q, R of the sides AB, BC and CA respectively.
The midpoint of two points, (x%5B1%5D, y%5B1%5D) and (x%5B2%5D, y%5B2%5D) is the point M found by the following formula:
M= (%28x%5B1%5D+%2B+x%5B2%5D%29%2F2,%28y%5B1%5D+%2B+y%5B2%5D%29%2F2)

the coordinates of the midpoint P, of the sides AB are:

P = (%282%2B+%28-2%29%29%2F2,%284+%2B+0%29%2F2)
​P = (0%2F2,4+%2F2)

P = (0,2)

the coordinates of the midpoint Q, of the sides BC are:
Q=(%28-2+%2B+6%29%2F2,%280+-1%29%2F2)
Q=(2,-1%2F2)
the coordinates of the midpoint R, of the sides CA are:
R= (%282%2B+6%29%2F2,%284-1%29%2F2)
R= (4,3%2F2)


(b) Find the equation of the medians AQ and BR, and the coordinates of the point were they intersect.
the equation of the medians:
AQ =>
first use points A(2,4) and Q=(2,-1%2F2) to find a slope
m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29
m=%28-1%2F2-4%29%2F%282-2%29
m=%28-1%2F2-4%29%2F0=> slope is undefined, and an undefined slope indicates that we have a vertical line parallel to the y-axis and passing through all points in the plane with an x-coordinate = constant ( c)
since both points A and Q have same x-coordinate, the equation of the median is
x=2


and BR
B(-2,0)
R= (4,3%2F2)
m=%283%2F2-0%29%2F%284-%28-2%29%29
m=%283%2F2%29%2F%284%2B2%29
m=%283%2F2%29%2F6....simplify
m=%28cross%283%291%2F2%29%2Fcross%286%292
m=1%2F4

now use point slope formula:

y-y%5B1%5D=m%28x-x%5B1%5D%29......plug in a slope and the coordinates of one point
y-0=%281%2F4%29%28x-%28-2%29%29
y=%281%2F4%29%28x%2B2%29
y=%281%2F4%29x%2B2%281%2F4%29
y=%281%2F4%29x%2B1%2F2


now find the coordinates of the point were they intersect:
x=2........eq.1
y=%281%2F4%29x%2B1%2F2.......eq.2
------------------------------------
y=%281%2F4%292%2B1%2F2
y=1%2F2%2B1%2F2
y=1

so, the coordinates of the point were they intersect is I=(2,1)
(c) Show that the third median CP also passes through this point
the third median CP:
C(6,-1)
P = (0,2)
first find the equation of the median:
m=%282-%28-1%29%29%2F%280-6%29
m=%282%2B1%29%2F%28-6%29
m=3%2F%28-6%29
m=-1%2F2
y-y%5B1%5D=m%28x-x%5B1%5D%29......plug in a slope and the coordinates of one point
y-2=-%281%2F2%29%28x-0%29
y-2=-%281%2F2%29x
y=-%281%2F2%29x%2B2

plug in coordinates I=(2,1)
1=-%281%2F2%292%2B2
1=-1%2B2
1=1=> which is true and confirms that the third median CP also passes through the point I=(2,1)