SOLUTION: A single die is rolled twice. The 36​ equally-likely outcomes are shown to the right. Find the probability of getting two numbers whose sum exceeds 16.

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Question 1141638: A single die is rolled twice. The 36​ equally-likely outcomes are shown to the right.
Find the probability of getting two numbers whose sum exceeds 16.

Found 2 solutions by jim_thompson5910, ikleyn:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Answer: 0

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Explanation:

Assuming we're dealing with a standard 6-sided die with labels from this set {1,2,3,4,5,6}, the largest sum possible is 6+6 = 12.

Therefore, it is not possible to get a sum of anything larger than 16, which is why the probability is 0.
Saying "the probability is 0" means the event will never happen.
It is equivalent to saying "there is a 0% chance of the event happening".


Answer by ikleyn(52821) About Me  (Show Source):
You can put this solution on YOUR website!
.
To learn this subject, look into the lesson
    - Rolling a pair of fair dice
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic  "Solved problems on Probability".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.