SOLUTION: A box of chocolates contains only milk, dark and white chocolates. The probability of picking out a milk chocolate if 3/8. If there are 24 dark chocolates and 6 white chocolate , h

Algebra ->  Statistics  -> Normal-probability -> SOLUTION: A box of chocolates contains only milk, dark and white chocolates. The probability of picking out a milk chocolate if 3/8. If there are 24 dark chocolates and 6 white chocolate , h      Log On


   

Question 1141626: A box of chocolates contains only milk, dark and white chocolates. The probability of picking out a milk chocolate if 3/8. If there are 24 dark chocolates and 6 white chocolate , how many milk chocolate are there?
Found 2 solutions by greenestamps, VFBundy:
Answer by greenestamps(13214) About Me  (Show Source):
You can put this solution on YOUR website!


P(milk chocolate) = 3/8, so P(dark or white chocolate) = 5/8.

The 5/8 probability for dark or white represents 24+6=30 chocolates.

So if x is the total number of chocolates in the box, then

%285%2F8%29x+=+30
x+=+30%288%2F5%29+=+48

And then the number of milk chocolates is

%283%2F8%29%2A48+=+3%2A6+=+18

Answer by VFBundy(438) About Me  (Show Source):
You can put this solution on YOUR website!
If the probability of picking a milk chocolate is 3/8, then the odds of picking either of the other two chocolates is 5/8. (Because: 1 - 3/8 = 5/8.)

We know there is a total of 30 "other" chocolates...chocolates that are NOT milk chocolate...since there are 24 dark chocolates and 6 white chocolates.

So, we know there are 30 "other" chocolates, and we know these chocolates account for 5/8 of the total number of chocolates.

To find the total number of chocolates, take the inverse of 5/8 and multiply this by 30:

8/5 * 30 = 240/5 = 48

So, we know there are 48 total chocolates. Since we know that 3/8 of the chocolates are milk chocolate, then:

3/8 * 48 = 144/8 = 18

So, there are 18 milk chocolates.