SOLUTION: The length of a rectangle is 5 inches longer than twice the width, and the area is 12 inches squared. Let l represent the length and w represent the width. Which of the following e

Algebra ->  Surface-area -> SOLUTION: The length of a rectangle is 5 inches longer than twice the width, and the area is 12 inches squared. Let l represent the length and w represent the width. Which of the following e      Log On


   

Question 1141583: The length of a rectangle is 5 inches longer than twice the width, and the area is 12 inches squared. Let l represent the length and w represent the width. Which of the following equations correctly models the situation?
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52877) About Me  (Show Source):
You can put this solution on YOUR website!
.

Nothing follows, so the post as it is presented makes no sense.


/\/\/\/\/\/\/\/

Dear visitor, 

     If your post asks "which of following . . . ",

     it means that something must follow.



     If you are not going to include what must follow - then modify your question correspondingly.


Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
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The length of a rectangle is 5 inches longer than twice the width, and the area is 12 inches squared. Let l represent the length and w represent the width. Which of the following equations ,....?
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Let L be length (not "l").
Let w be width.

L=2w%2B5, and w, the dimensions

Lw=12
%282w%2B5%29w=12
w%282w%2B5=12%29--------OR you could take the L equation and solve for w, and then form the area equation in terms of L, and put into whatever form of equation you want.