SOLUTION: Beth can travel 208 miles in the same time it takes Anna to travel 192 miles. If Beth's speed is 4 mph greater than Anna's, find both rates.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Beth can travel 208 miles in the same time it takes Anna to travel 192 miles. If Beth's speed is 4 mph greater than Anna's, find both rates.      Log On


   



Question 1141377: Beth can travel 208 miles in the same time it takes Anna to travel 192 miles. If Beth's speed is 4 mph greater than Anna's, find both rates.
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Anna travels at x mph and takes xt hours to go 192 miles
Beth travels at (x+4) mph and takes xt hours to go 208 miles
t for Anna is 192/x
t for Beth is 208/(x+4)
those t s are equal, so that (192/x)=208/(x+4)
cross multiply so that 192x+768=208cx
16x=768
x=48 mph for Anna
x+4=52 mph for Beth
4 hours will be t.